SPOJ Problem 1
When I saw that Thor had done solutions to the first few problems of Project Euler in many many languages, I thought "Hey! That's a good idea!" but didn't want to copy exactly.
So instead I'm doing solutions to some problems on SPOJ. SPOJ is an online judge system full of algorithmic problems. This is one of the things that Hanson Wang did to get as good as he is. The solutions I'll be providing here are going to be very simple problems, so don't expect any magic. The beautiful thing about SPOJ is the sheer number of languages it will judge. I figured this was the perfect playground to make sure my code worked in all the languages I try.
Problem: Life, the Universe, and Everything
Your program is to use the brute-force approach in order to find the Answer to Life, the Universe, and Everything. More precisely... rewrite small numbers from input to output. Stop processing input after reading in the number 42. All numbers at input are integers of one or two digits.
Solutions - In order of frequency that I use the language
C++
1 2 3 4 5 6 7 8 9 10 11 12 13 | //TEST AC - CPP (g++) #include <iostream> using namespace std; int main() { int n; while(1) { cin >> n; if (n == 42) break; cout << n << endl; } return 0; } |
C99
1 2 3 4 5 6 7 8 9 10 11 | //TEST AC - (gcc C99) #include <stdio.h> int main() { int n; while(1) { scanf("%d",&n); if (n == 42) break; printf("%d\n",n); } return 0; } |
php
1 2 3 4 5 6 7 8 | <? //TEST AC - PHP while(1) { fscanf(STDIN,"%d",$n); if ($n == 42) break; print "$n\n"; } ?> |
Python
1 2 3 4 5 6 | #TEST AC - Python while 1: num = input() if (num == 42): break print num |
Bash
1 2 3 4 5 6 7 8 9 10 | #!/bin/bash # TEST AC - BASH while true; do read n if [ $n -eq 42 ]; then break fi echo "$n" done |
Ruby
1 2 3 4 5 6 7 8 | #TEST AC - Ruby while 1 n = gets.to_i if n == 42 break end puts n end |
Java
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 | //TEST AC - Java import java.io.*; import java.util.*; public class Main { public static void main(String[] args) { Scanner in = new Scanner(System.in); while(true) { int n = in.nextInt(); if (n == 42) break; System.out.println(n); } } } |
Perl
1 2 3 4 5 6 7 8 9 | #TEST AC - Perl while (1) { $n = <STDIN>; if ($n == 42) { last; } print $n } |
C#
1 2 3 4 5 6 7 8 9 10 11 12 | //TEST AC - C# (gmcs + Mono) using System; class WelcomeCSS { static void Main() { while(true) { int n; n = int.Parse(Console.ReadLine()); if (n == 42) break; Console.WriteLine(n); } } } |
GNU Pascal
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 | {TEST AC - GPC Pascal} program TEST; var n:integer; begin while true do begin readln(n); if n = 42 then begin break; end; writeln(n); end; end. |
You can see Thor's Project Euler solutions here: Derek Thurn's Website - Project Euler